In the torsion formula tau = T*r/J, if the outer radius is halved while torque and the polar moment of inertia remain constant, how does the shear stress change?

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Multiple Choice

In the torsion formula tau = T*r/J, if the outer radius is halved while torque and the polar moment of inertia remain constant, how does the shear stress change?

Explanation:
The shear stress in torsion scales with radius when torque and the polar moment are fixed, because tau = T*r/J. If the outer radius is halved and T and J stay the same, tau becomes T*(r/2)/J, which is half of the original tau. So the shear stress is halved.

The shear stress in torsion scales with radius when torque and the polar moment are fixed, because tau = Tr/J. If the outer radius is halved and T and J stay the same, tau becomes T(r/2)/J, which is half of the original tau. So the shear stress is halved.

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